Question

simplify completely (x^2-3x-54/x^2-18x+81)*(x^2+12x+36/x+6) please :) I'm a little stuck

Answer 1

\[ \frac{x^2-3x-54}{x^2-18x+81}\times\frac{x^2+12x+36}{x+6}\]

Answer 2

yes! that is much clearer than the way I wrote it, but can you explain what steps you use ti solve it?

Answer 3

i mean simplify***

Answer 4

ok so there are two numerators (the bit a the top of a fraction) and two denominators (the bit at the bottom of the fraction),

factorize each of these in to something like (x+...)(x+...)
{the x+6 can not be factorized further

then look to cancel common bracketed terms that are in the numerator and the denominator

Answer 5

so the final outcome of (x+6)^2 / x-9 would make sense right ?

Answer 6

that looks great

Answer 7

thanks so much!