find the largest number which divides 398,436 nd 542 leavin remainder 7,11 nd 15 respectivly

Question

anonymous · Answer

@apoorvk

apoorvk · Answer

Let that no. be 'x'.
Now if 298 would have been 7 less, i.e. 391, then it would have been perfectly divisible by 'x'. 

Agree?

anonymous · Answer

ya

anonymous · Answer

its 398 nt 298

apoorvk · Answer

similarly, for 436 and 542, if they had been 11 and 15 less respectively, that is 425 and 527, then 'x' would have divided them exactly.

lol yes *398.

anonymous · Answer

lol!!!
 ur a genius....nw i jst hav 2 tak de hcf ryt??

apoorvk · Answer

so, that means, 391, 425 and 527 are completely divisible by 'x'.

Now, what is the greatest no. that divides all 3 of them? Remember HCF?

apoorvk · Answer

Yes, right, the HCF! great work!

No, not me, you are the genius! :)

anonymous · Answer

:D