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find the largest number which divides 398,436 nd 542 leavin remainder 7,11 nd 15 respectivly
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@apoorvk
Let that no. be 'x'. Now if 298 would have been 7 less, i.e. 391, then it would have been perfectly divisible by 'x'. Agree?
ya
its 398 nt 298
similarly, for 436 and 542, if they had been 11 and 15 less respectively, that is 425 and 527, then 'x' would have divided them exactly. lol yes *398.
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lol!!! ur a genius....nw i jst hav 2 tak de hcf ryt??
so, that means, 391, 425 and 527 are completely divisible by 'x'. Now, what is the greatest no. that divides all 3 of them? Remember HCF?
Yes, right, the HCF! great work! No, not me, you are the genius! :)
:D
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