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Mathematics 19 Online
OpenStudy (anonymous):

find the largest number which divides 398,436 nd 542 leavin remainder 7,11 nd 15 respectivly

OpenStudy (anonymous):

@apoorvk

OpenStudy (apoorvk):

Let that no. be 'x'. Now if 298 would have been 7 less, i.e. 391, then it would have been perfectly divisible by 'x'. Agree?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

its 398 nt 298

OpenStudy (apoorvk):

similarly, for 436 and 542, if they had been 11 and 15 less respectively, that is 425 and 527, then 'x' would have divided them exactly. lol yes *398.

OpenStudy (anonymous):

lol!!! ur a genius....nw i jst hav 2 tak de hcf ryt??

OpenStudy (apoorvk):

so, that means, 391, 425 and 527 are completely divisible by 'x'. Now, what is the greatest no. that divides all 3 of them? Remember HCF?

OpenStudy (apoorvk):

Yes, right, the HCF! great work! No, not me, you are the genius! :)

OpenStudy (anonymous):

:D

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