Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x^2 - 6x + 1 = 0

three real-number roots

two real-number roots

one real-number root

no real-number roots

Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x^2 - 6x + 1 = 0

       three real-number roots

       two real-number roots

       one real-number root

       no real-number roots

anonymous · Answer

what do you think it is?

anonymous · Answer

Lol I Dont Know :S

anonymous · Answer

can you give me the value of the discriminant?

anonymous · Answer

discriminant = b^2 - 4(a)(c)....  in $\large ax^2+bx+c=0  $

anonymous · Answer

can you at least identify 
a=
b=
c=

???

anonymous · Answer

compare your equation with $\large ax^2+bx+c=0  $ and match up the coefficients...

anonymous · Answer

hello?

anonymous · Answer

Oh Sorry This Is Not My Math Its My Sisters And Im Helping Her So I dont Know Much :/

anonymous · Answer

i think she'd learn better if you let her do her own work, don't you think?   :)

anonymous · Answer

|dw:1339186297993:dw| since the number is positive, there are 2 real solutions.