Question

A bag contains 10 blue, 6 red, and 4 green rubber balls. If you select a ball at random from the bag, what is the probability of not choosing a green ball? Explain why it is reasonable to eliminate choice D, even though the denominator of choice D is appropriate.

I know that the answer would be 4/5 but why is it reasonable to eliminate D?

Answer 1

And what is choice D?

Answer 2

9/10

Answer 3

Sorry, forgot to add that.

Answer 4

how many balls are not green?

Answer 5

16

Answer 6

how many balls are there in total?

Answer 7

20

Answer 8

now divide the two numbers

Answer 9

Divide 16 by 20?

Answer 10

Or each number by 4?

Answer 11

16 divided by 20

Answer 12

Which equals 0.8.

Answer 13

\[\frac{16}{20}=\frac{8}{10}=\frac{4}{5}=.8\]

Answer 14

Ok, I get it now. Thank you for your help. :)

Answer 15

no problem