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(3x^3)^3= a.27x^9 b.27x^6 c.9x^9 d.9x^6
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\[(3x ^{3})^{3} = 3^{3}x ^{3*3} = 27x ^{9}\]
why would you move the x?
lol he didn't?
so then why is it 3^3x?
He used the rules of exponents. The outside ^3 is distributed to the inside 3 and 3^3 Then 3^3 = 27 x^3^3 = x^3*3 = x^9 So the final answer was 27x^9
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