Question

Check my DE work?

Answer 1

I think that I'm close but wolfram disagrees with me and if I take the first derivative of my solution and evaluate it at 0 it dosen't equal 1

Answer 2

\[L^{-1}(\frac{s}{(s+1)^2+1})=e^{-t}(\cos(t)-\sin(t))\]not e^(-t)cos(t)

Answer 3

http://www.wolframalpha.com/input/?i=laplace+inverse+%28s%2F%28%28s%2B1%29%5E2%2B1%29%29

check the alternate forms

Answer 4

@gmer

Answer 5

Thanks much! I see how I made that mistake now, gotta watch that while I get ready for the test :)

Answer 6

:D ur welcome... Goodluck:)