Question

Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps below. Find the step where Harry went wrong.

Answer 1

First of all, do you know what the quadratic formula is?

Answer 2

Yes.

Answer 3

I wrote this problem out 6 times, still can't see WHERE he went wrong.

Answer 4

What are you corresponding 'a', 'b' and 'c' for this quadratic when you compare it with the standard equation of a quadratic "ax^2 + bx +c=0"?

Answer 5

A = 2. B = -1. C = -6.

Answer 6

\[1 \pm \sqrt{-1^{2}} - 4*2*-6\]

Answer 7

-12 * -4 = 48.
1*1 = 1. \[1 \pm \sqrt{1-48 } \div 2\]

Answer 8

So it would be

Answer 9

Step 3?

Answer 10

STEP 2!!!

Answer 11

He + instead of -.

Answer 12

Should be :
\[x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4 \times 3 \times (-6) }{} }{2\times 2 }\]

Answer 13

No, it'd be -6.

Answer 14

-4 * 2 * -6.

Answer 15

actually the second step itself ha the error.
(-1)^2 = 1


and yes that would be -4*2*-6 --> typo my bad.

Answer 16

*has

Answer 17

So, it's step 2, right?

Answer 18

Yup!

Answer 19

I have one more question.

Answer 20

And please ask questions in the correct subject forum :)

Answer 21

Sure, just post it as a new one!

Answer 22

Oh wow, I didn't realize I was in biology