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Chemistry
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Solve 2^(x + 3) = 7
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its Solving Exponential Equations with Unequal Bases
take the log of both sides. Then, because of the properties of logs, you can take the exponent down, so it looks like this: (x+3) log 2 = log 7 then just solve for x, by dividing both sides by log 2, then subtracting 3. Always be sure to check your answer. (Just a note, this question really belongs in Mathematics, not Chemistry)
OMG im srry :( i thought it was math ill change the question haha
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