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Use the following to determine the distance A (13,7) B (-9,4). 1) 5 2) √493 3) √137 4) √112
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distance equals \[\sqrt{(4-7)^{2}+(-9-13)^{2}}=\sqrt{493}\]
Use the distance formula: \[d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}\]
draw a picture and then find some lengths |dw:1339300073075:dw| a right triangle is formed... used pythagoras' theorem to find d d^2 = 22^2 + 3^2 \[d = \sqrt{493}\]
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