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What is the formula for the surface area of revolution about the y-axis?
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make x the subject.
\[2\pi\int_{a}^{b}x(y)\sqrt {1 + \left( {dx \over dy} \right)^2} dy\]
\[\int_a^b 2\pi y\ ds\] where ds is the arc length differential.
i am trying to find the surface area of a sphere
\[x^2+y^2=r^2\]\[x=\sqrt{r^2-y^2}\]\[y=\sqrt{r^2-x^2}\]
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That results in kind of a nasty integral, better off using 4(pi)r^2 if you can
i know the result, i am trying to show the formula works
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