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OpenStudy (aravindg):
first of all note that this is hat shaped graph symmetrical about -1
OpenStudy (aravindg):
so wat do u think for which value of x we get macximum value of y?
OpenStudy (aravindg):
@esmeier1434
OpenStudy (anonymous):
I have no clue.. :/
OpenStudy (aravindg):
u should have :) i iencourage my friends to think rather than mug up
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OpenStudy (anonymous):
use differentiation :)
OpenStudy (anonymous):
easy as hell man !
OpenStudy (aravindg):
@esmeier1434 any doubts?
OpenStudy (anonymous):
I just dont get this whole unit i have been working on..
OpenStudy (aravindg):
which grade u in?
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OpenStudy (anonymous):
senior
OpenStudy (aravindg):
means?
OpenStudy (aravindg):
11?
OpenStudy (anonymous):
12
OpenStudy (aravindg):
:P i am also 12
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OpenStudy (aravindg):
i learnt quadratics in grade 9
OpenStudy (anonymous):
oh
OpenStudy (aravindg):
nw i am playing with integrals and differentials :P
OpenStudy (anonymous):
:/ i suck at math
OpenStudy (aravindg):
first try to change that attitude !!
try to like the subject
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OpenStudy (aravindg):
then u will learn it easily
OpenStudy (aravindg):
here is a quote for u
"dont run after succes chase excellence success will follow u"
OpenStudy (anonymous):
\[y=-x^2-2x+3\\ \text{The vertex is given by }\\( \frac{-b}{2a} \ , \ \frac{4ac-b^2}{4a})\\\\ \text{Substitute to get : }\\\\ \frac{-(-2)}{2(-1)} \ , \ \frac{4(-1)(3)-(-2)^2}{4(-1)}\\\\ \text{The vertex is }\\(-1, 4) \]