Question

I need help!

What are the solutions of the system?

y= x^2 - 2x - 2
y= 4x + 5

Answer 1

a. (-1,1) and (-7,-23)
b. (-1,1) and (7,23)
c. (-1,33) and (7, 1)
d. no solution

Answer 2

substitute the expression fo y from the first equation into the second, giving\[4x+5=x^2-2x-2\]which can be put into the form\[ax^2+bx+c=0\]and solved by factoring, completing the square, or the quadratic formula.

Answer 3

for*

Answer 4

I am confused....

Answer 5

if both \(a=c\) and \(b=c\)
then \(a=b\)

does that make sense?

Answer 6

not really... sorry I am so bad at algebra

Answer 7

well this is not an easy problem if you are "bad" at algebra (don't jump to conclusions, I felt that way once too)

do you know the quadratic formula?

Answer 8

yes... kinda

Answer 9

ax2 + bx + c", right?

Answer 10

the quadratic formula is that for equations of the form\[ax^2+bx+c=0\]we have\[x={-b\pm\sqrt{b^2-4ac}\over2a}\]

Answer 11

now we want to make a substitutionsince both expressions with x are equal to y we can substitute