Question

see problem below please help

Answer 1

the domain of the function
f:x-->x^ 3-5 is D=(0,1,2,3,4) find the range of

Answer 2

sorry

Answer 3

Substitute the values of 0, 1, 2, 3 and 4 in the function f: x -> x^3 - 5.
f(0) = (0)^3 - 5 = - 5
f(1) = (1)^3 - 5 = - 4
f(2) = 8 - 5 = 3
f(3) = 27 - 5 = 22
f(4) = 64 - 5 = 59
R = { - 5, - 4, 3, 22, 59 }

Answer 4

why is it R tho?

Answer 5

oh

Answer 6

right i get it that was simple

Answer 7

r is the range

Answer 8

thanks i really had no clue before

Answer 9

ur welcome

Answer 10

i appreciate it :)