Question

Use the quadratic formula to solve the equation,
2x^2-3x=-5...I came up with x=1/4(3-i√31

Answer 1

\(\huge x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \)
a=2
b=-3
c=5
so
\(\huge x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(5)}}{2(2)} \)
\(\huge x=\frac{3\pm\sqrt{9-40}}{4} \)
\(\huge x=\frac{3\pm \sqrt{-31}}{4} \)
\(\huge x=\frac{3\pm i\sqrt{31}}{4} \)