Question

Factor completely.
6x^5-48x^4+12^3

Answer 1

Factor the GCF first.
i.e. x^3

Answer 2

x^3(6x^2-48x+12)

Now 6 is common too!

6x^3(x^2 - 8x + 2)

Answer 3

Take 6 as common
=>6(x^5-8x^4+2^3)

Answer 4

@saifoo.khan u can't take x^3 as common

Answer 5

@TheViper , Yes, we can.

Answer 6

6x^5-48x^5+12^4

Answer 7

How plz tell me:)

Answer 8

@alisa845 , you changed the exponents?

Answer 9

@TheViper , I just showed the steps.

Answer 10

xis not present in 12^3

Answer 11

I think that's a typo. :P

Answer 12

Guys, you're both (kinda) right. The common factor is \(6x^3\).

Answer 13

typo?

Answer 14

it's 12x^3 not 12^3
@TheViper

Answer 15

oh! but not written in the question

Answer 16

It's a typo. :P

Answer 17

So I was confused

Answer 18

Is ur question \[6x^5-48x^4+12x^3\]

Answer 19

Rewrite the question plz:)

Answer 20

Factor completely.
6x^5-48x^4+12^3