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A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5. h = height t = time in seconds Find the maximum height of the ball. a) 13.9 feet b) 8.3 feet c) 12.2 feet d) 7.6 feet
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if this were a graph, you would find the vertex by doing \[-\frac{b} {2a}\] so, for this, the vertex/maximum is at -32/-32, or t = 1 second. now plug in 1 for t, and you get the max height.
this is a recurring problem... the answer in those choices is not listed...
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