Question

quadratic equation by completing the square. check both roots . equation below

Answer 1

\[x^2-6x=7\]

Answer 2

please explain each step

Answer 3

well, first subtract 7 from both sides.

Answer 4

take half of 6 get 3 write
\[(x-3)^2=7+...\] then think "3 squared is 9" write
\[(x-3)^2=7+9=16\] take the root, don't forget the \(\pm\) get
\[x-3=\pm\sqrt{16}\]
\[x-3=\pm4\]

Answer 5

then solve
\[x-3=4\iff x=7\] or
\[x-3=-4\iff x=-1\]

Answer 6

all the steps are there

Answer 7

wow i think i get it let me try it on paper

Answer 8

hmm thats not right

Answer 9

wait my mistake you got half right but there is supposed to be one more answer

Answer 10

no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.

Answer 11

you are right my bad again i didnt see or