quadratic equation by completing the square. check both roots . equation below

Question

anonymous · Answer

$$x^2-6x=7$$

anonymous · Answer

please explain each step

nottim · Answer

well, first subtract 7 from both sides.

anonymous · Answer

take half of 6 get 3 write 
$$(x-3)^2=7+...$$ then think "3 squared is 9" write 
$$(x-3)^2=7+9=16$$ take the root, don't forget the $\pm$ get 
$$x-3=\pm\sqrt{16}$$
$$x-3=\pm4$$

anonymous · Answer

then solve 
$$x-3=4\iff x=7$$ or 
$$x-3=-4\iff x=-1$$

anonymous · Answer

all the steps are there

anonymous · Answer

wow i think i get it let me try it on paper

anonymous · Answer

hmm thats not right

anonymous · Answer

wait my mistake you got half right but there is supposed to be one more answer

nottim · Answer

no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.

anonymous · Answer

you are right my bad again i didnt see or