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2x-9(under radical)=1/3
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do you mean 2x - 9 = 1/3
\[\sqrt{2x-9}=1/3\]
Ok that makes more sense
Square both sides to eliminate the radical and then solve for \(x\) :)
\(\sqrt{2x-9}= \frac{1}{3}\) \(2x-9 = \frac{1}{3}^{2}\)
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What dont you understand about this question
just making sure i'm doing it correctly.
Ok. Just square both sides, this will give 2x - 9 = (1/9) now multiply both sides by 9, this will give 18x - 81 = 1 Add 81 to both sides 18x = 82 x = 82/18
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