please can anyone tell me if this is right???
find the lim as x--infinity 5x^7+3x^2-14/9x^5-11x^7+32 my answer is.....

Question

please can anyone tell me if this is right???
find the lim as x-->infinity   5x^7+3x^2-14/9x^5-11x^7+32 my answer is.....

anonymous · Answer

x=-5/11?

anonymous · Answer

is that right?

anonymous · Answer

anyone?

anonymous · Answer

-.- plz! help me i REALLY need help!

ujjwal · Answer

that should be -infinity .. How do you get -5/11? can you show steps?

anonymous · Answer

yeah! :)
since getting the horizontal asyptote id the same as getting the limit and getting the horizontal asymptote is first gathered from looking at the power of the leading coefficient....they are both raised to the power of seven....well once reorganized so then it'll be 5/-11 ??????is this correct?

ujjwal · Answer

see this. http://www.wolframalpha.com/input/?i=limit+x+tends+to+infinity++5x%5E7%2B3x%5E2-%2814%2F9%29x%5E5-11x%5E7%2B32

anonymous · Answer

thanks this explains so much.