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Factor 2x^3+x^2-14x-7?
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\[ 2x^3+x^2-14x-7\]
(2x+1)([x^{2}+7])
isn't it minus 7?
Factor out \[x ^{2}\] from the first part so you get \[x ^{2}(2x+1)\] and then factor a 7 from that second part \[-7(2x+1)\] Since there are 2 (2x+1), they basically become one and whatever is left over is your other term \[(x ^{2}+7)\]
yeah, -7 sorry
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Its Okay. I was off to.
But thank you for replying and helping me :D
No problem :)
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