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Tricky. If x^2+x=3, then x^4+x= ?
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\[x^{2}+x=3, x ^{4}+x= ?\]
it is a system of equations right? Solve for one and pluge it into the other
No, MCQs: a) x^2+3 b) 4(3-x) C) 3(x-1) D) 6(2-x)
still solve for the first and plug in to the second eq
Can't solve for the first
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I don't know how to solve
use the quadratic formula
this is an odd one the options you are given wouldn't work. Maybe it is asking something different but idk what.
It is 6(2-x)
Try to see why.
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\[ x^4 + x= x(x^3+1)= x(x+1) ( x^2 - x +1)=\\ (x^2 +x)( (x^2 +x) -x -x +1)= 3( 3 -2x + 1)=3( 4 -2 x)=6(2-x) \]
Thank you so much Elia, however, I figured this out in the morning today lol.
Excellent
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