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I tried to use the F=MA, where F = 12, and m = 2 and I got 6 but apparently its 4.
Since both of the blocks are being moved by the force, you need to consider the blocks collectively, and thus the sum of their masses.\[F = (m_A + m_B)a \longrightarrow \boxed{a = \dfrac{F}{m_A + m_B}}\]Does that make sense?
Yes I get it, thank you!
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