Question

Multiply and simplify:
http://roads.advancedacademics.com/contentserver/content/roadssection/277572/questions/9hw2/9hw2_q5.gif

I can post the options if needed (:

Answer 1

A: http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/277572/Questions/9HW2/9HW2_q5a1.gif

B: http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/277572/Questions/9HW2/9HW2_q5a2.gif

C: http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/277572/Questions/9HW2/9HW2_q5a3.gif

Answer 2

\[\frac{10x^2}{6y^3} \times \frac{24y^2}{35x^2}=\frac{2\times 5x^2}{6y^3} \times \frac{4 \times 6 y^2}{7 \times 5x^2} = ...?\]Can you cross out the common factors

Answer 3

i dont know what you mean.. i suck at these kinds of questions

Answer 4

What are the common factors in both numerator and denominator?

Answer 5

One of the them : 6
Can you find the others?

Answer 6

.... :/

Answer 7

.... won't help much :)
Can you at least try a little - doesn't matter if it is right or not..

Answer 8

im not sure which numbers your asking about? the ones you came up with or the ones in the question?

Answer 9

im sooo confused haha sorry

Answer 10

\[\frac{10x^2}{6y^3} \times \frac{24y^2}{35x^2}\]\[=\frac{2\times 5x^2}{6y^3} \times \frac{4 \times 6 y^2}{7 \times 5x^2} \]The second line here

Answer 11

I broke the original number down into some factors so that you can do the cancelling job easier.

Answer 12

i think i got B, is that right?

Answer 13

Nope, there are some unknowns that can be cancelled.

Answer 14

i dont know what to do then..

Answer 15

cancel the common factors... there are many.... one of them is 6, another is 4 and you can also see the x and y ...

Answer 16

C?

Answer 17

How did you get the answer?

Answer 18

honestly? i guessed :/ i just dont get it

Answer 19

Honestly - it is
But I don't agree with guessing when someone is trying to help you understand.

Answer 20

i know im sorry. thank you for helping

Answer 21

I really hope that you can learn.. Or else you'll get into trouble soon. Anyway, good luck!

Answer 22

i hope so too, thanks!