Question

evaluate 5 combination 2 / 6 permutation 2

Answer 1

5 combination 2 is \[\frac{5!}{2!(5-2)!}\] na @ParthKohli ?

Answer 2

and 6 permutation 2 is \[\frac{6!}{2!}?\]

Answer 3

\( \color{Black}{\Rightarrow nPr = \Large {n! \over (n -r)!} }\)

\( \color{Black}{\Rightarrow nCr = \Large{nPr \over r!} }\)

Answer 4

@lgbasallote 6p2 = 6!/4!

Answer 5

oh yeah! but the combo was right?

Answer 6

Yep :)

Answer 7

Evaluate them individually, then divide.

Answer 8

great! im beginning to get used to this lol

Answer 9

Yeah it's fun