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Find the coordinates of the foci for the ellipse: (x + 3)2/9 + (y - 1)2/25 = 1
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I think you have a typo. What you have written is a linear equation, not an ellipse. Can you write it in the form of the following please? This isn't logical as written, sorry. \[(x/a)^2+(x/b)^2=1\] (a & b are constants) If you can do that then you can find the focus using one of the following (remember the E mean's eccentricity, whereas a is the longer radius and b is the shorter radius, radius from the center/centroiod that is): \[f=a *\epsilon=\sqrt{a^2-b^2}\] I believe this should get you toward finding your answer ;-)
(x+3)^(2)/(9)+(y-1)^(2)/(25)=1
(-3, -3) and (-3, 5) as seen here:
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