Question

Express in simplest form: x2-1/x2+3x+2 Helpp please

Answer 1

\[x^2 - 1 = (x+1)(x-1)\]
\[x^2 + 3x + 2 = (x+1)(x+2)\]

therefore \[\frac{x^2-1}{x^2 + 3x + 2} = \frac{(x+1)(x-1)}{(x+1)(x+2)}\]

Answer 2

cancel like terms in numerator and denominator

Answer 3

do you get that @taty555 ?

Answer 4

ohh I understand now

Answer 5

great!!