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If sin y°=7 over q and tan y°=7 over r, what is the value of cos y°?
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this is the figure they provided but where did they get the q and r? and 7 for that matter? I am confused....
make triangle relations. sin = opposite/hypotenuse, tan=opposite/adjacent, cos=adjacent/hypotenuse. So:|dw:1339706553045:dw|By that, cos y = r/q
that makes so much more sense why couldnt they have done that??
they want to see you analyze the side relationships of trig functions.
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trig is no joke!
thank you for showing me that it helped a lot
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