what is the domain and range of y= |3x-5| and |6x^2-4x-3| it is absolute value and i know that domain must be ALL REAL NUMBERS but what is range?

Question

anonymous · Answer

the range for |3x-5| is [0, inf)
the range for |6x^2-4x-3| is also [0, inf)

all the absolute value does is whatever y value that is negative gets relected over the x axis making it positive.

anonymous · Answer

is y>0? for both equations?

jim_thompson5910 · Answer

More like $$\Large y \ge 0$$ but you have the right idea

anonymous · Answer

so why x= allrealnumbers and y is greater than or less than o and also all real numbers?

anonymous · Answer

*or equal to

jim_thompson5910 · Answer

x is any real number since you can plug in any real number and get some number out

jim_thompson5910 · Answer

y >= 0 because the absolute value of any number is either positive or 0

anonymous · Answer

why isn't y also all real numbers greater than or equal to 0?

jim_thompson5910 · Answer

it's not all real numbers since you won't get any negative numbers for y