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Mathematics
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OpenStudy (anonymous):
help me please
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OpenStudy (anonymous):
OpenStudy (anonymous):
take any 2 points from the lines
calculate change in rise/change in run
this will be your gradient m
The equation for a straight line is y = mx + c
OpenStudy (anonymous):
? :o what?
ganeshie8 (ganeshie8):
y = -2x -3
interpret the graph. can you see the line is falling as we go right ?
so slope is -ve for such graphs. do you know how to calculate slope ?
OpenStudy (anonymous):
is it y2-yl / x2-x1 when you find the solution?
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ganeshie8 (ganeshie8):
correct. you can take any two points on the line and compute the slope.
u will get the same number. try it now..
OpenStudy (anonymous):
so can i take any two points from this one then do the y2-yl
ganeshie8 (ganeshie8):
mathematically yes. but we will take the points : (-4, 4) and (0, -1)
can you locate them in your graph ?
OpenStudy (anonymous):
yes is it -5/4
ganeshie8 (ganeshie8):
poerfect. can you frame the equation of line now ?
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OpenStudy (anonymous):
is it y=-5/4x-1?
ganeshie8 (ganeshie8):
correct... you are tooo good badatmath !!!!!
OpenStudy (anonymous):
Thank you :)
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