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Mathematics 17 Online
OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

OpenStudy (anonymous):

take any 2 points from the lines calculate change in rise/change in run this will be your gradient m The equation for a straight line is y = mx + c

OpenStudy (anonymous):

? :o what?

ganeshie8 (ganeshie8):

y = -2x -3 interpret the graph. can you see the line is falling as we go right ? so slope is -ve for such graphs. do you know how to calculate slope ?

OpenStudy (anonymous):

is it y2-yl / x2-x1 when you find the solution?

ganeshie8 (ganeshie8):

correct. you can take any two points on the line and compute the slope. u will get the same number. try it now..

OpenStudy (anonymous):

so can i take any two points from this one then do the y2-yl

ganeshie8 (ganeshie8):

mathematically yes. but we will take the points : (-4, 4) and (0, -1) can you locate them in your graph ?

OpenStudy (anonymous):

yes is it -5/4

ganeshie8 (ganeshie8):

poerfect. can you frame the equation of line now ?

OpenStudy (anonymous):

is it y=-5/4x-1?

ganeshie8 (ganeshie8):

correct... you are tooo good badatmath !!!!!

OpenStudy (anonymous):

Thank you :)

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