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What is the sum of the measures of the interior angles of a regular polygon where a single exterior angle measures 36°?
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the sum of all exterior angles = 360 so you have a decagon here sum of interior angles = 10 * (180-36)
10 * 144
Well, you know the sum of the interior angles for a polygon with \(n\) sides is \((n-2)180^\circ\), so if we divide that into \(n\) equal angles (the number of interior angles in such a regular polygon\), we get the following expression for the magnitude of each angle:\[\frac{n-2}{n}180^\circ\]Set that equal to \(36^\circ\) and solve for \(n\).
okay, thank you! I got that answer too :)
yw
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