Question

{x+2 0 14 years ago

Answer 1

At the boundaries of the pieces (i.e., \(x=1\) and \(x=2\)), see if the adjacent pieces align up.

Answer 2

Explain @yakeyglee

Answer 3

@angela210793 @AccessDenied @Agent_Sniffles @Austin_Rain @physicsme @SmoothMath

Answer 4

\(x+2\) and \(x\) are both adjacent to \(x=1\) (it's where one ends and the other beings). Do they have the same value at that point?

Answer 5

@Outkast3r09 @vikayefremova @lalaly @LokoRay