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Mathematics 13 Online
OpenStudy (anonymous):

Determine the limit (attached on the picture) it is just a one number answer, can someone check it out?

OpenStudy (anonymous):

OpenStudy (angela210793):

what's the function???

OpenStudy (anonymous):

y = f(x) that's all it is given

OpenStudy (anonymous):

i remember the teacher said the answer is the slope of the point? but i'm not sure

OpenStudy (angela210793):

i think it's -3 cause -3 is an asymptote in here right

OpenStudy (angela210793):

cause y=-3 is an asymptote i meant***

OpenStudy (campbell_st):

on the graph the function has a point of discontinuity are x = -2 so the limit should be 3

OpenStudy (campbell_st):

oop y = 3

OpenStudy (angela210793):

3 or -3 O.o|dw:1339792861887:dw|

OpenStudy (anonymous):

isnt it 3 .. since the y is 3 when x = 2?

OpenStudy (anonymous):

and plus it is x-> -2+ so it is not going to -3 asymtote tho

OpenStudy (campbell_st):

have a look at x = -2... and go up to y = 3... thats a point of discontinuity

OpenStudy (angela210793):

im actually talkkng abt this one O.o im confused :S|dw:1339792966245:dw|

OpenStudy (campbell_st):

the graph doesn't exist at that point

OpenStudy (angela210793):

so lim doesnt exist at x=-2 O.o

OpenStudy (campbell_st):

the limit exists.... bit its value is 3....

OpenStudy (anonymous):

oh ok, thanks! so it is nothing about "slopes" right?

OpenStudy (campbell_st):

the little circle idicates a break in the curve... why is it broken at, because x can't get to the value of y = 3, thats the feature that exists at x = -2

OpenStudy (anonymous):

oh, i think i understand what u are saying, thanks! so the answer will be the same for -2- and -2 + ?

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