Question

let y = 80/(1+6e^(-2t)) Find the exact co-ordinates of the point where the function is the steepest

Answer 1

i got (0.89588, 40) as the co-ordinates

Answer 2

\[\huge y=\frac{80}{1+6e^{-2t}} \]
that's it?

Answer 3

yup

Answer 4

we'll need to take the second derivative... do you have that?

Answer 5

yup i got it as -1920e^(2t) (e^2t) - 6 / ((e^2x) + 6)^3

Answer 6

i found the first derivative to be maximum at x = 0.89588

Answer 7

yup... looks like your answer of x=(ln6)/2 is correct.. i didn't check the y value though...

Answer 8

ok... i just checked... you're good....:)

Answer 9

kk thanks :)

Answer 10

yw...:)