PLEASE HELP! Determine the equation of the line that passes through B(3,-1) and is perpendicular to the line defined by 2x+y-9=0.
First you need to put the equation into y=mx + b form. Do you know how to do this?
Are we suppose to take out the 0?
Yes you just need to isolate y.
y=2x - 9?
Close your signs are wrong though
which ones are wrong?
Remember when you want to move stuff around you need to do the operation so you are taking away 2x from each side and adding 9 to each side so it cancels on the left and is moved to the right understand?
It should be y = -2x + 9 know what I mean?
why are we puting 2x as a negative though?
Do you know how to do algebra?
Yes but, im so confused right now
Okay if you have y-5= 0 what does y= ?
Oh shoot sorry! I get it now
Since i want to transfer 2x and -9 to the other side i have to put it in the other operations as -2x and +9 right?
=) that's okay. So now we have it in the form we need that was step one next we need the negative inverse of the slop because a line that is perpendicular will have a negative inverse slope do you know how to find this? Yes that is correct =).
Would the -2x become as a 1/2? I dont know i did long time ago
Correct so now you know the slope of your perpendicular line do you want to write out what it looks like so far?
y= 1/2 + 9
Wait the slope of are new equation is (1/2) in y = mx +b the slope is "m" and we don't know what b is yet.
oh sorry!!!!! y=1/2x + 9
close
we don't know what b= so what should be in the place of b?
do we plug in (3,-1) to variables of x and y?
yes and solve for b because right now we have y = (1/2)x + b and we have a point on the line so we can solve for b like you said do you want to try that now?
y= 1/2x + 9 (-1) =1/2(3) + 9 (-1) =1.5 + 9 (-1) = 10.5 -11.5? i dont think this is right... :(
You don't know what b is you are trying to solve for b do you know what I mean?
you have y = (1/2)x + b you need to plug in your points and solve for b.
sorry! y=(1/2)x + b (-1) = (1/2)(3) + b (-1) = (1.5) + b (-1) - (1.5) = b -2.5 = b
Looks good to me so what is your equation?
y= 1/2x - 2.5?
Correct =) good job
but it says in my book that it's x-2y-5=0....?
multiply everything by 2 and solve for zero to get it into that form. Doing this isn't changing the equation all the points will be the same.
That should say + 5
So the equation can be what we just did right? it doesn't have to be the form in which my book did it?
Not unless the teacher wants you to put it into that form.
Are you sure the one in the book doesn't say x - 2y + 5 = 0 ?
how do i put it in that form though? and no it doesnt say +5 :(
oh my bad sorry I got confused it should say -5 haha
Anyway you just multiply everything in the equation had by 2 and then you move everything to the left side and set the right to zero know what I mean?
not exactly...
2*y = 2*((1/2)x + 2.5) what does it look like after doing this?
2y=y +5 and the you put the x and 5 on the other side?
right =)
so its a 2y= -x -5?
wait look at what you typed
you need 2y - x - 5 = 0
So you don't put the equals sign?
what did the equation in the book say?
x-2y-5=0
okay so if you have 2y = x - 5 then you need to move the stuff on the right onto the left, and then you would have is -x+ 2y + 5 = 0 but what you need is x - 2y - 5= 0 so you multiply the equation by -1 and then you are done. Honestly these steps are pointless but it is just the way you make it look like the one in the book.
This is really confusing but i think i get it.... Why did you multiply by 2 in the first place though from the previous one?
In order to get the same coefficients
Oh alright, THANK YOU SO MUCH! :)
No problem you solved it =)
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