Question

Evaluate

f(x) = 2x5 -3x4 + x3 - 6x + 20: x = 2
1. 32
2. 10
3. 8
4. 4

Answer 1

Did you try replacing x with 2?

Answer 2

Then use order of operations

Answer 3

ok super duper easy
substitute 2 for x
f(2)=2(2)^5-3(2)^4+2^3-6(2)+20
f(2)= ?
Im pretty sure you can figure it ou from there

Answer 4

okay i got 10, is that correct?

Answer 5

I think you should try again
I'm getting something different

Answer 6

pkay hold on im horrible at math

Answer 7

38?

Answer 8

Lets try this by hand
We have
\[2(2)^5-3(2)^4+(2)^3-6(2)+20\]
Do you know the order of operations?

Answer 9

We have no grouping symbols
But we do have exponents
Evaluate all that has exponent first
What do we get?

Answer 10

\[2^5=?\]
\[2^4=?\]
\[2^3=?\]

Answer 11

so do the exponents matter?

Answer 12

Yes they matter

Answer 13

That is why we are doing something with them

Answer 14

\[2 \neq 2^5\]

Answer 15

b/c \[2^5=32 \neq 2\]
Do exponents matter big time

Answer 16

Order of operations tells us to take care of the exponents so that is what we are doing
I asked you 3 questions above
can you answer them?

Answer 17

First put the value of x in the equation.Then what will u got is the ans.:)

Answer 18

\[\Huge{\color{red}{f(x)=2x^5-3x^4+x^3-6x+20}}\]\[\LARGE{\color{green}{f(2)=2(2)^5-3(2)^4+(2)^3-6(2)+20}}\]\[\LARGE{\color{green}{\implies(2\times32)-(3\times16)+8-12+20}}\]\[\LARGE{\color{green}{\implies64-48+8-12+20}}\]\[\Huge{\color{gold}{\star \star}{32Ans.}}\]