solve the following for the principal values of the indicated variable. 3cosx-1=2
isolate cosx first
okay..but how do i get rid of it?
divide by cos?
step by step add +1 both sides
i got that..cosx = 1
great! now what is principal value ?
idk..lol
let me google... i dont remember either lol
cosine of what angle gives 1 ?
adj. over hyp.
but..idk...
here.. use the unit circle... page 3 http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
i dont understand that..
oh.... sorry, you have'nt used the unit circle yet?
i have..but im so frustrated with this crap..i don't feeling like trying to comprehend that...i've never used it for this..
my apologies.... i didn't mean to offend u...
you didn't..just tell me what the next step is
let's just use your definition of cosine then: \[\huge cos(\theta)=\frac{adjacent}{hypotenuse}=1 \] the only time this can occur is when the adjacent side is the same length as the hypotenuse. this means the angle is 0. so cos(0)=1. the principal value is 0
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