Graph the following conditions.

{(x, y): x + 2y

Question

Graph the following conditions.

{(x, y): x + 2y < 6}

anonymous · Answer

ok so the little"<" thing that a line below it

anonymous · Answer

solve for y  and plot normally   then...

anonymous · Answer

the answers i have are in pics

anonymous · Answer

y <= 3-(1/2)*x 

 choose a point for x any point like 0  then  y=< 3  therefore shade below line make the line solid

anonymous · Answer

https://www.google.com/search?rlz=1C1CHFX_enUS470US470&aq=f&sugexp=chrome,mod=18&sourceid=chrome&ie=UTF-8&q=3-(1%2F2)*x looks like that with the shading under the line

anonymous · Answer

This site is really helpful https://www.desmos.com/calculator

callisto · Answer

First draw the line for x+2y = 6. Since it's with less than or equal to, the line is a solid line.
To draw the line, 
Put x =0, 
0 + 2y = 6   => y=3
So, (0,3) is one of the points lying on the straight line.

Put y = 0
x + 2(0) =6    => x=6
So, (6, 0) is another point lying on on the straight line.

Now, draw x-axis and y-axis on a piece of graph paper. Mark the scale. Plot the 2 points on the graph. Draw a straight line joining the two points. Write the equation (x+2y=6) near the line. 

To determine the shaded region, put a point to test. For instance, consider the point (0, 0)
LS = 0 + 2(0) = 0 < 6
So, it satisfies the condition. That means the point (0, 0) is in the shaded region. Then, shade the region where (0, 0) is located at.

anonymous · Answer

how would teh graph look like?

anonymous · Answer

https://www.google.com/search?rlz=1C1CHFX_enUS470US470&aq=f&sugexp=chrome,mod=18&sourceid=chrome&ie=UTF-8&q=3-(1%2F2)*x with the bottom of line shaded in

callisto · Answer

Have you drawn it?

anonymous · Answer

^^ not in my answers

callisto · Answer

If you draw it, you'll know the answer.

anonymous · Answer

oh than like the google link i gave with it shaded above :P

callisto · Answer

I've mentioned it quite clearly in my previous post. Which one you don't know?

anonymous · Answer

sorry i got it thanks:D

callisto · Answer

I just quoted from my previous post.
To draw the line, 
Put x =0, 
0 + 2y = 6   => y=3
So, (0,3) is one of the points lying on the straight line.

Put y = 0
x + 2(0) =6    => x=6
So, (6, 0) is another point lying on on the straight line.

anonymous · Answer

sorry i got it thanks:D

callisto · Answer

Welcome