Help?

Given the circle having a diameter with endpoints (-2, 1) and (6, 7).

The equation would be (x-2)^2 + (y-4)^2 =

Question

Help?

Given the circle having a diameter with endpoints (-2, 1) and (6, 7).

The equation would be (x-2)^2 + (y-4)^2 =

anonymous · Answer

is it 17?

anonymous · Answer

You have to first find the mid-point of those two points. And the midpoint of the diameter will be your radius. This is the equation of a circle, which in standard form is (x-h)^2+(y-k)^2=r^2. Where (h,k) is the center and r is the radius. Thus, you have to find r so plug in x and y from same set of the points and solve for r.
When i did that I got zero, but am a little unsure about this question.

anonymous · Answer

hmm. okay. thanks anyway:)

anonymous · Answer

You're welcome. But do you understand the method to my madness? Lol... maybe bump it again and see what someone else says...

anonymous · Answer

ah! woops, i closed it already. i understand. i think.

anonymous · Answer

turns out it was 25. :|

anonymous · Answer

But it says given the circle having diameter