Question

Factor this..?

Answer 1

\[16s ^{4}-81\]

Answer 2

Please show steps! :)

Answer 3

\[\huge{16s^4-81}\]
\[\huge{(4s^2)^2-(9)^2}\]

apply \(\huge{a^2-b^2=(a+b)(a-b)}\)

Answer 4

\[\huge 16s^4 - 81 \implies (4s^2)^2 - (9)^2\]

difference of two squares ^_^

Answer 5

try to apply the identity ... and then post here what you get

Answer 6

I see, so you're trying to get it at the same power??

Answer 7

what you should usually look out for is difference of two squares and sum and difference of cubes ;)

Answer 8

Ah, okay thank you!