A banner in the shape of an isosceles triangle has a base that is 2 inches shorter than either of the equal sides. If the perimeter of the banner is 43 inches, then what is the length of the equal sides?

Question

anonymous · Answer

Let the length of the equal sides be $x$ inches then:

$2x + x-2 = 43 \implies 3x = 45 \implies x = 15 $ inches

radar · Answer

We know that the sum of the three sides (the perimeter) is 43 inches.
Let x = lenght of one of the equal sides
then the base is x-2 inches (given)
lets add up the three sides
x-2 + x + x which is 3x-2 and equal to 43
3x-2 = 43
3x=45
x=15 in.   the equal sides are 15, and the base is 15-2 or 13 inches.

anonymous · Answer

okay i figured u would do it like that but i wasnt sure thanks u 2.