Question

What is the simplest form for a to the power of 9 b to the power of 5 over a to the power of 3 b to the power of 15

Answer 1

can you draw the powers

Answer 2

Is that what you're trying to say? \[(A^{9} B^{5} ) \div (A^{3} B^{15})\]

Answer 3

@Wired yes! :)

Answer 4

@Wired

Answer 5

when dividing subtract the powers for the same base

\[\frac{x^a}{x^b} = x^{a -b}\]

so you have \[a^{9-3}\times b^{5 - 15}\]

negative powers indicate fractions

\[x^{-b} = \frac{1}{x^b}\]

hope this helps

Answer 6

@Wired helppleaseeee

Answer 7

campbell already gave you the proper equations.