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derivative of sqrt(x)
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from the definition??
so I was curious why the answer was \[\frac{1}{2\sqrt{x}}\] but that would be because \[x^1/2\] goes to x^-1/2 which would be that answer right?
\[\frac d{dx}(x^n)=nx^{n-1}\]your exponent is right, but think about your coefficient
sqrt x = x^1/2 Bring the 1/2 to the front, subtract the power by 1 so 1/2 x^-1/2 \[1/(2\sqrt{x})\]
yup so\[\frac{1}{2 \sqrt{x}}\]
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right :)
:)
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