Question

does anyone know how to work this problem out? it says solve this equation by the method of substitution: 2x-4y=-14
-x-6y=-5

Answer 1

\[\Huge{2x-4y=-14}\]
First solve this equation for x

\[\Huge{2x=-14+4y}\]
\[\Huge{x=\frac{-14-4y}{2}}\]
\[\Huge{x=-7-2y}\]

Answer 2

now put the value of x that you get in the second equation ... can you do it now ?

Answer 3

let me try it!

Answer 4

ok

Answer 5

for the x= -7-2y do i divide by -2 to cancel the 2y out?

Answer 6

no why r u cancelling .. let it be there

Answer 7

\[\Huge{x-6y=-5}\]
\[\Huge{(-7-2y-6y=-5}\]

Answer 8

solve this now

Answer 9

oh! sorry! im so confused :(

Answer 10

how do i find out the value of x, so i can plug it in the second equation?

Answer 11

Ok let me start a new solution for you ..

Answer 12

just see the first equation

Answer 13

Can you solve for x ?

Answer 14

don't you do
-2x?

Answer 15

right subtract 2x from both sides what you get ?

Answer 16

-4y= 16?

Answer 17

see if you subtract 2x on LHS then you should also on RHS

\[\Huge{2x-2x-4y=-14-2x}\]
\[\Huge{-4y=-14-2x}\]

Answer 18

Now solve for x :: can you do it now ?

Answer 19

i got -4y+2x=-14

Answer 20

is probably not right

Answer 21

\[\Huge{-4y+14=-2x}\]

Answer 22

oh ok

Answer 23

then divide both sides by (-2)

Answer 24

i mean i know the answer but i just want someone teach me step by step on how to get that answer

Answer 25

did u get this yet..

Answer 26

divide both sides which are?

Answer 27

-2x and -4y?

Answer 28

-4y+14 and -2x