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Solve the equation. 4 times the square root of x minus 5 minus 8 = 12
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\[4\sqrt{x-5}-8=12\] Is this what you are asking?
yes
First step is get rid of that annoying radical sign :), but how?
by square rooting it i think
\[4\sqrt{x-5}-8=12\] \[4\sqrt{x-5}=20\] Divide both sides by 4 \[\sqrt{x-5}=5\] Square both sides to get rid of the root \[x-5=25\] \[x=20\] Makes sense? :)
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x=30 sorry!
It does make sense :)
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