Need help VERY badly.

Question

anonymous · Answer

Expand (x + 3)6 using Pascal’s Triangle

kainui · Answer

How many terms do you need to go?

anonymous · Answer

it does not say how far to go..

kainui · Answer

Well look at this picture. See how every number is the sum of the two numbers right above it? http://www.mathsisfun.com/images/pascals-triangle-2.gif Just do that!

anonymous · Answer

I know how to do it.  I just dont know how to start it... since the equation is (x+3)^6

kainui · Answer

Just pretend (x+3)^6 is 1 and try to do what's happening to 1. So you can put that equation in all along the sides of the triangle and at the top where it says 2 you put in 2(x+3)^6 because you're adding them together since (x+3)^6+(x+3)^6=2(x+3)^6. So basically all those numbers are just your coefficients!

jim_thompson5910 · Answer

Look at the row that starts with 1, 6, 15, ...


The first value in that row (1) will multiply with x^6*(3)^0 to get 1*x^6 = x^6

The second value in that row (6) will multiply with x^5*3^1 = 3x^5 to get 6*3x^5 =18x^5

etc etc

anonymous · Answer

Thank you!!!!!