Find the equation in standard form which passes through (–2, –7) and (1, –1). You must show all work. i got -2x+7=-5 can someone help me
how'd you come upon this answer?
You form should be written in: y=mx+c There is no y in this equation :s?
i use the point slope formula
point slope formula states \[y-y_1=m(x-x_1)\] you'll always have a y and x with a coefficient
yah so is what i got correct
no because your y in the equation never came out
what did you get for your slope
i got 2
correct now using one of those points with m=2 you get \[y-(-1)=2(x-1)
\[y-(-1)=2(x-1)\]
\[y+1=2x-2\]
should i plug in my point (1,-1) into the y=mx +b formula to get y=2x-3 which in standard form is y-2x=-3
mx+b is slope intercept form you can only use this if you know the y intercept
you need to use the point slope formula
oh okay i accidentally messed up the 2(x-1) i missed the negative and that messed me up. So the answer would be y-2x=-3
yes
Thank you so much!!
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