Help!!!!!!!!
Solve for x :
log(base3)(4.3^x-1) = 2x+1

Question

anonymous · Answer

help quickly friends!!!!!!!

ganeshie8 · Answer

$$\log_{3}(4 * 3^{(x-1)}) = 2x+1 $$

ganeshie8 · Answer

you equations looks like above ?

anonymous · Answer

no it is a decimal point.

anonymous · Answer

4.3(power-x)-1

anonymous · Answer

is it 4 into 3 to power (x-1) or 4*3 to power (x) -1
i.e. 4*3^(x-1) or 4*3^(x) -1

ganeshie8 · Answer

$$\log_{3}(4.3^{x}-1) = 2x-1 $$

anonymous · Answer

it is 4.3 to the power x

ganeshie8 · Answer

ok it looks like above is it ?

anonymous · Answer

yes ganesh's equation is right

ganeshie8 · Answer

this doesnt look simple to me to solve... leaving it to himanshu..  :)

anonymous · Answer

solve 4.3^x-1=3^(2x+1) to get x

anonymous · Answer

log$$\log_{3}(4.3^{x}-1)=2x+1$$

shubhamsrg · Answer

it'd require the knowledge of higher mathematics (interpolation in this case) i'd guess//

anonymous · Answer

first u have to cancel the log..
to do this write (2x+1) as log(base 3) 3^(2x+1)

shubhamsrg · Answer

unless its 4 * (3^x) which makes it quad eqn..

anonymous · Answer

i want an answer

shubhamsrg · Answer

it must be 4 * (3^x) buddy,,am damn sure..(though i may be wrong :P)

anonymous · Answer

ok solve it as 4*(3^x)....................

shubhamsrg · Answer

let 3^x = y
so you'll have 
3y^2 - 4y + 1 =0 = (3y-1)(y-1)
=> y =1 and 1/3
so x =0 and -1

anonymous · Answer

x=0 and x=-1

anonymous · Answer

thanks himanshu and shubham

anonymous · Answer

you are correct

anonymous · Answer

one more thiing when u solve for x for these question which contain log try to verify for all values of x u have found..there may be a case u get negative in a log for some x. u have to discasr that value of x

anonymous · Answer

*discard

anonymous · Answer

ok thanks

shubhamsrg · Answer

hmmn,, :)