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Write an exponential function y=ab^2 for a graph that includes (2,24) and (3,48)
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plug and solve for a and b
i think there is a mistake in the question \[ab^2=a\times b\times b\] is not an exponential function
maybe it is \(y=a\times b^x\) ?
ab^x sorry.
ok then first you solve for \(b\) since you know \[a\times b^3=48\] and \[a\times b^2=24\] and \[\frac{a\times b^3}{a\times b^2}=b=\frac{48}{24}=2\] so you have \(b=2\)
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It was 24
?
now that we have \(b=2\) we know \(a\times 2^2=24\) so \(4a=24\) and therefore \(a=6\) and your function is \[y=6\times 2^x\]
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