Trigonometry, help! (Please view picture for correct equation format) This was explained to me the other day (the method for solving) but I don't know how to apply it to this problem. I was hoping someone can walk me through the steps. Any help is appreciated!

Question

anonymous · Answer

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anonymous · Answer

treat it like a quadratic equation...
you'll be solving this eqauation:  $\large 3m^2−2m-1=0 $,  where $\large m=tan^2θ $

anonymous · Answer

Alrighty, thank you @dpaInc Sorry I'm answering late :p

anonymous · Answer

yw... still need me to continue?

anonymous · Answer

If you don't mind (: I'm not sure what to do once I've done that

anonymous · Answer

ok... i don't mind... 
can you solve $\large 3m^2-2m-1=0 $

anonymous · Answer

Would the next step result in something like this? (m - 2)(m - 1)=0

anonymous · Answer

Wait, no :/ That doesn't equal 3m^2 - 2m - 1 =0

anonymous · Answer

yes you have to factor but that will not give a 3 as the coefficient of the m^2 term...
try again...

anonymous · Answer

Right

anonymous · Answer

The closest thing I'm getting is (3m - 1)(m + 1) but that doesn't give me a negative one :/

anonymous · Answer

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