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Mathematics 10 Online
OpenStudy (anonymous):

Suppose that an experiment is repeated four times. A certain event has probability in a single repetition of the experiment. What is the probability that it occurs in the fourth trial only? 1/4 9/10,000 729/10,000

OpenStudy (anonymous):

They explained it on there. I just found it and yeah hope it helps :)

OpenStudy (anonymous):

haha smarty pants

OpenStudy (anonymous):

That's where I find lots of the answers I need for virtual school help :) Or I just come here :)

OpenStudy (anonymous):

okay well i have question three from that website you just gave me and the answer on that website isnt on my qquestion???

OpenStudy (anonymous):

Well on the website it's .0729/1. Now if we move the decimal point 4 spots to the right on both sides, we get 729/10,000

OpenStudy (anonymous):

thats not one either lol

OpenStudy (anonymous):

It's on your choices... the last choice up above.

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

2/5 1/40 1/10,000 these are the choices now

OpenStudy (anonymous):

im not as dumb as i look

OpenStudy (anonymous):

Sry, it's just I don't see the choices. For what problem, are the new choices?

OpenStudy (anonymous):

problem three

OpenStudy (anonymous):

Oh okay. sry thought you were talking about the problem up there. Well on the website it says the answer is (1/10)^4. That means we do 1/10*1/10*1/10*1/10. And that's 1/10,000.

OpenStudy (anonymous):

your too smart

OpenStudy (anonymous):

i loove you lol jk but really you got me a hundred

OpenStudy (anonymous):

Lol congratz :) and lol is it virtual school?

OpenStudy (anonymous):

yea :( you any good at CONDITIONAL PROBABILITY

OpenStudy (anonymous):

Lol I do FLVS(Florida Virtual School) for some classes. I can try to help you :)

OpenStudy (anonymous):

your a life savor

OpenStudy (anonymous):

Lol thx. Hopefully I can help :)

OpenStudy (anonymous):

A box of 6 coins (penny, nickel, dime or quarter) worth $0.67 is shaken. What is the probability that a nickel is drawn first and then a quarter? Assume no replacement and that all coins are equally likely.

OpenStudy (anonymous):

Well the probability of getting a nickel is 1/6. Then for a quarter it's 2/5 cause there has to be 2 of them in there, to make the problem correct. 1/6*2/5=1/15

OpenStudy (anonymous):

if its wrong im coming to beat you up lol

OpenStudy (anonymous):

for it to be .67 cents there has to be 2quarters, 1dime,1nickel,2 pennies. Lol *runs away to another question*

OpenStudy (anonymous):

haha you suck

OpenStudy (anonymous):

Lol, any other questions?

OpenStudy (anonymous):

The letters of the word Mississippi are placed in a hat. What is the probability that the first two letters drawn are both i if the first letter drawn is not replaced? i know im a dummy

OpenStudy (anonymous):

Lol no you aren't. I know this one kid in my school who has like a 1.8 GPA who is so dumb and has no life.

OpenStudy (anonymous):

hey hey now thats not very nice

OpenStudy (anonymous):

Well it's true, I mean he plays video games the whole time and even talks about them while changing for PE and every moment of his life.

OpenStudy (anonymous):

K so in Mississippi there are 4 i's. and 11 letters. The first one will be 4/11, and the 2nd time will be 3/10 probability. Multiply these together and you get 12/110 which goes down to approximately .11

OpenStudy (anonymous):

...

OpenStudy (anonymous):

i got another hundred you are the bomb lol

OpenStudy (anonymous):

Omg lol are you serious? wow my quiz only has 7 questions (5-10?'s the most)

OpenStudy (anonymous):

what are you working on? maybe i can help im good at some stuff

OpenStudy (anonymous):

i don't believe you...

OpenStudy (anonymous):

Well it's Alg. II and just finished. Was about matrices.

OpenStudy (anonymous):

thats easy

OpenStudy (anonymous):

You've done Alg. II?

OpenStudy (anonymous):

thats what im in silly

OpenStudy (anonymous):

Oh, lol I'm on module 2 of the 10 there are in my virutal class for Alg. II

OpenStudy (anonymous):

hit me with your best question

OpenStudy (anonymous):

Lol, the matrices are easy. I'll give you a question though.

OpenStudy (anonymous):

What is the solution to the following system using Cramer’s Rule? 2x + 2y = 14 x – 3y = –17

OpenStudy (anonymous):

(1, 6) (6, 1) (–6, –1) (–1, –6)

OpenStudy (anonymous):

isnt it the first one?

OpenStudy (anonymous):

CORRECT

OpenStudy (anonymous):

see im not stupid ish

OpenStudy (anonymous):

I never said that.

OpenStudy (anonymous):

and I didn't think that. Just saying, g2g soon. so one more problem or no?

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